3 Responses for "ruby Arrayで組み合わせを出力する方法"

1. ujihisa August 11th, 2008 at 3:07 am

   それArray#combinationで。

   >> (1..10).to_a.combination(3).to_a
   => [[1, 2, 3], [1, 2, 4], [1, 2, 5], [1, 2, 6], [1, 2, 7], [1, 2, 8], [1, 2, 9], [1, 2, 10], [1, 3, 4], [1, 3, 5], [1, 3, 6], [1, 3, 7], [1, 3, 8], [1, 3, 9], [1, 3, 10], [1, 4, 5], [1, 4, 6], [1, 4, 7], [1, 4, 8], [1, 4, 9], [1, 4, 10], [1, 5, 6], [1, 5, 7], [1, 5, 8], [1, 5, 9], [1, 5, 10], [1, 6, 7], [1, 6, 8], [1, 6, 9], [1, 6, 10], [1, 7, 8], [1, 7, 9], [1, 7, 10], [1, 8, 9], [1, 8, 10], [1, 9, 10], [2, 3, 4], [2, 3, 5], [2, 3, 6], [2, 3, 7], [2, 3, 8], [2, 3, 9], [2, 3, 10], [2, 4, 5], [2, 4, 6], [2, 4, 7], [2, 4, 8], [2, 4, 9], [2, 4, 10], [2, 5, 6], [2, 5, 7], [2, 5, 8], [2, 5, 9], [2, 5, 10], [2, 6, 7], [2, 6, 8], [2, 6, 9], [2, 6, 10], [2, 7, 8], [2, 7, 9], [2, 7, 10], [2, 8, 9], [2, 8, 10], [2, 9, 10], [3, 4, 5], [3, 4, 6], [3, 4, 7], [3, 4, 8], [3, 4, 9], [3, 4, 10], [3, 5, 6], [3, 5, 7], [3, 5, 8], [3, 5, 9], [3, 5, 10], [3, 6, 7], [3, 6, 8], [3, 6, 9], [3, 6, 10], [3, 7, 8], [3, 7, 9], [3, 7, 10], [3, 8, 9], [3, 8, 10], [3, 9, 10], [4, 5, 6], [4, 5, 7], [4, 5, 8], [4, 5, 9], [4, 5, 10], [4, 6, 7], [4, 6, 8], [4, 6, 9], [4, 6, 10], [4, 7, 8], [4, 7, 9], [4, 7, 10], [4, 8, 9], [4, 8, 10], [4, 9, 10], [5, 6, 7], [5, 6, 8], [5, 6, 9], [5, 6, 10], [5, 7, 8], [5, 7, 9], [5, 7, 10], [5, 8, 9], [5, 8, 10], [5, 9, 10], [6, 7, 8], [6, 7, 9], [6, 7, 10], [6, 8, 9], [6, 8, 10], [6, 9, 10], [7, 8, 9], [7, 8, 10], [7, 9, 10], [8, 9, 10]]

   Ruby 1.8.7の話

2. alan smithy August 11th, 2008 at 7:02 pm

   それhaskellのone linerで(ry

3. harajune August 12th, 2008 at 12:04 am

   >ujihisa
   おろ。関数あったのか。けど探すより書いたほうが早かった・・・

   >alan
   再起なのでたぶん関数型言語だと簡単に書けそうですね。
   haskellはテンプレートマッチも使えるからたぶんもうちょいスマートな感じにもなりそう。